Z80 Undocumented Instructions
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Is you want to participate, please E-mail some found Undocumented Instructions.
Thomas Scherrer
By: Jacco J.T. Bot
At your request for documentation on the extra z80 instructions
I've dug into my subdirectories and out came a file which is listed below.
I hope it helps understanding the Z80, most instructions are a direct result of the way it is microcoded.
That is also visible in an instruction like LD A,HL.
There is the 3-byte fast function and the #ED prefix one, which is considerably slower but implemented anyway when the Great ChipMaker decided to expand the instructionset with LD A,BC; LD A,DE;
The way these instructions are decoded implements automatically the LD A,HL instruction for the second time.
Why Zilog is silent about the next bunch of instructions is a mystery to me.
But they also make the Z800, the Z8000, the Z180, the Z280 and the Z380 which must al be compatible on instruction
level so maybe the extra z80 instructions aren't implemented in
one of these.
Who cares anyway, lets get to the :)
Undocumented Z80 instructions
----------------------------------------------
If an opcode works with the registers HL, H or L then if that
opcode is preceded by #DD (or #FD) it works on IX, IXH or IXL
(or IY, IYH, IYL), with some exceptions.
The exeptions are instructions like LD H,IXH and LD L,IYH
because it isn't clear from the opcode on which register the
prefix (#FD or #DD) should operate, so from the opcodes point
of view we can read LD H,IXH but also LD IXH, H and obviously
LD IXH,IXH doesn't do us any good, does it?
Instructions like LD IXH,IXL should work but I didn't test
them yet, my debugger went bananas and is now retired to the
afterlife for computerprograms...
I also have doubts about the usefullness and correctness of
the OUT (C),F instruction.
The IN (C), F instructions is only usefull if you test bits
which have the same number as a flag in the F-register because
some older Z80 lock up otherwise.
An instruction which uses the #ED and the #DD (or #FD) prefix
is also invalid,
so IN IXH,(C) which should translate to DD ED .. is NOT valid.
Anyway, here's a list of valid, but undocumented by Zilog,
instructions...
These instructions are tested on: Z80A, Z80B and Z80H.
OPCODE INSTRUCTION OPCODE INSTRUCTION
----------- ----------------- ------------ ------------
#DD #24 INC IXH #FD #24 INC IYH
#DD #25 DEC IXH #FD #25 DEC IYH
#DD #26 nn LD IXH,nn #FD #26 nn LD IYH,nn
#DD #2C INC IXL #FD #2C INC IYL
#DD #2D DEC IXL #FD #2D DEC IYL
#DD #2E nn LD IXL,nn #FD #2E nn LD IYL,nn
#DD #44 LD B,IXH #FD #44 LD B,IYH
#DD #45 LD B,IXL #FD #45 LD B,IYL
#DD #4C LD C,IXH #FD #4C LD C,IYH
#DD #4D LD C,IXL #FD #4D LD C,IYL
#DD #54 LD D,IXH #FD #54 LD D,IYH
#DD #55 LD D,IXL #FD #55 LD D,IYL
#DD #5C LD E,IXH #FD #5C LD E,IYH
#DD #5D LD E,IXL #FD #5D LD E,IYL
#DD #60 LD IXH,B #FD #60 LD IYH,B
#DD #61 LD IXH,C #FD #61 LD IYH,C
#DD #62 LD IXH,D #FD #62 LD IYH,D
#DD #63 LD IXH,E #FD #63 LD IYH,E
#DD #64 LD IXH,IXH #FD #64 LD IYH,IYH
#DD #65 LD IXH,IXL #FD #65 LD IYH,IYL
#DD #67 LD IXH,A #FD #67 LD IYH,A
#DD #68 LD IXL,B #FD #68 LD IYL,B
#DD #69 LD IXL,C #FD #69 LD IYL,C
#DD #6A LD IXL,D #FD #6A LD IYL,D
#DD #6B LD IXL,E #FD #6B LD IYL,E
#DD #6C LD IXL,IXH #FD #6C LD IYL,IYH
#DD #6D LD IXL,IXL #FD #6D LD IYL,IYL
#DD #6F LD IXL,A #FD #6F LD IYL,A
#DD #7C LD A,IXH #FD #7C LD A,IYH
#DD #7D LD A,IXL #FD #7D LD A,IYL
#DD #84 ADD A,IXH #FD #84 ADD A,IYH
#DD #85 ADD A,IXL #FD #85 ADD A,IYL
#DD #8C ADC A,IXH #FD #8C ADC A,IYH
#DD #8D ADC A,IXL #FD #8D ADC A,IYL
#DD #94 SUB IXH #FD #94 SUB IYH
#DD #95 SUB IXL #FD #95 SUB IYL
#DD #9C SBC A,IXH #FD #9C SBC A,IYH
#DD #9D SBC A,IXL #FD #9D SBC A,IYL
#DD #A4 AND IXH #FD #A4 AND IYH
#DD #A5 AND IXL #FD #A5 AND IYL
#DD #AC XOR IXH #FD #AC XOR IYH
#DD #AD XOR IXL #FD #AD XOR IYL
#DD #B4 OR IXH #FD #B4 OR IYH
#DD #B5 OR IXL #FD #B5 OR IYL
#DD #BC CP IXH #FD #BC CP IYH
#DD #BD CP IXL #FD #BD CP IYL
#DD #CB nn #00 RLC (IX+nn) & LD B,(IX+nn) 1)
#DD #CB nn #01 RLC (IX+nn) & LD C,(IX+nn)
#DD #CB nn #02 RLC (IX+nn) & LD D,(IX+nn)
#DD #CB nn #03 RLC (IX+nn) & LD E,(IX+nn)
#DD #CB nn #04 RLC (IX+nn) & LD H,(IX+nn)
#DD #CB nn #05 RLC (IX+nn) & LD L,(IX+nn)
#DD #CB nn #06 RLC (IX+nn) & LD F,(IX+nn)
#DD #CB nn #07 RLC (IX+nn) & LD A,(IX+nn)
#DD #CB nn #08 RRC (IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #10 RL (IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #18 RR (IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #20 SLA (IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #28 SRA (IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #30 SLL (IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #38 SRL (IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #80 RES 0,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #88 RES 1,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #90 RES 2,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #98 RES 3,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #A0 RES 4,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #A8 RES 5,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #B0 RES 6,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #B8 RES 7,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #C0 SET 0,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #C8 SET 1,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #D0 SET 2,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #D8 SET 3,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #E0 SET 4,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #E8 SET 5,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #F0 SET 6,(IX+nn) & LD B,(IX+nn) etc.
#DD #CB nn #F8 SET 7,(IX+nn) & LD B,(IX+nn) etc.
#CB #30 SLL B 2)
#CB #31 SLL C
#CB #32 SLL D
#CB #33 SLL E
#CB #34 SLL H
#CB #35 SLL L
#CB #36 SLL (HL)
#CB #37 SLL A
#ED #70 IN F,(C)
#ED #71 OUT F,(C) (?)
All the above instructions also work with IY, IYH and IYL,
just replace #DD for #FD.
NOTES:
1) These instructions are strange because in fact they are
two instructions in one.
Lets examine the folowing line
#DD #CB nn #00 RLC (IX+nn) & LD B,(IX+nn)
The value at address (IX+nn) is left rotated through the
carry AND is loaded in the B register. I bet that some sophisticated
programmers may make excellent use of these commands but I reccomend
against using them because its task it not obvious from the opcode,
and my assembler doesn't (YET) support them, I've got to find a nice
short symbol for them, maybe something like RLC(IX+nn)->B.
2) These instructions are equivalent to the SLA command. That is
perfectly logical:
An arithmethic rightshift (SRA) has to preserve the 7-th (sign)bit, A
logical rightshift (SRL) doesn't. The arithmetic leftshift doesn't
preserve anything, in two's complement the 6-th bit becomes the sign.
A logical leftshift hasn't got anything to do with signbits so it also
doesn't preserve any bits. The difference is the way we look at the
resulting number, a 8-bit byte or a 7-bit integer with 1 sign-bit.
Original list by Richard Spijkers, 1992 ricosoftware.
Translated and Updated by Jacco Bot, 1996 JBSoft
MORE Undocumented Z80 Opcodes
Operations with the High and Low Bytes of IX and IY
- HX and LX are the high and low bytes of IX.
- HY and LY are the high and low bytes of IY.
- To use HX and HY, prefix opcodes that use H with $DD
for HX and with $FD for HY.
- To use LX and LY, prefix opcodes that use L with $DD
for LX and by $FD for LY.
Examples
- To get LD HX,A use .DB $DD followed by
LD H,A.
- To get CP LY use .DB $FD followed by
CP L.
The following instructions support this feature:
- ADC
- ADD
- AND
- CP
- DEC
- INC
- OR
- SBC
- SUB
- XOR
- LD rd,nn
- LD rd,rs (except LD HX,(IX+nn)
and the like)
Shift Left with One Insertion (SL1)
- This instruction operates like SLA, except that a 1 is inserted
into the low bit of the operand.
- This instruction is inappropriately called SLL in other documents.
(Probably for symmetry in the naming scheme.)
Instruction Opcode r
SL1 r CB 30+r 0 B 4 H
SL1 (IX+nn) DD CB nn 36 1 C 5 L
SL1 (IY+nn) FD CB nn 36 2 D 6 (HL)
3 E 7 A
Bit Operations with Autocopy
- These instructions perform their operations and also load the result
into a register.
- Instructions using IY can be formed by substituting $FD for
$DD in the opcode.
- The missing chunk in the opcode space from 40+r to 78+r
is for BIT commands, which do not support autocopy.
Instruction Opcode r
RLC r,(IX+nn) DD CB nn 00+r 0 B
RRC r,(IX+nn) DD CB nn 08+r 1 C
RL r,(IX+nn) DD CB nn 10+r 2 D
RR r,(IX+nn) DD CB nn 18+r 3 E
SLA r,(IX+nn) DD CB nn 20+r 4 H
SRA r,(IX+nn) DD CB nn 28+r 5 L
SL1 r,(IX+nn) DD CB nn 30+r 6 no autocopy (documented)
SRL r,(IX+nn) DD CB nn 38+r 7 A
RES r,0,(IX+nn) DD CB nn 80+r
RES r,1,(IX+nn) DD CB nn 88+r
RES r,2,(IX+nn) DD CB nn 90+r
RES r,3,(IX+nn) DD CB nn 98+r
RES r,4,(IX+nn) DD CB nn A0+r
RES r,5,(IX+nn) DD CB nn A8+r
RES r,6,(IX+nn) DD CB nn B0+r
RES r,7,(IX+nn) DD CB nn B8+r
SET r,0,(IX+nn) DD CB nn C0+r
SET r,1,(IX+nn) DD CB nn C8+r
SET r,2,(IX+nn) DD CB nn D0+r
SET r,3,(IX+nn) DD CB nn D8+r
SET r,4,(IX+nn) DD CB nn E0+r
SET r,5,(IX+nn) DD CB nn E8+r
SET r,6,(IX+nn) DD CB nn F0+r
SET r,7,(IX+nn) DD CB nn F8+r
Null Input and Output
Instruction Opcode Description
IN (C) ED 70 Input from port C, but alter flags only.
OUT (C),0 ED 71 Output 0 to port C.
EVEN MORE Undocumented Z80 Opcodes
--------- F r o m N O R T H E R N B Y T E S V o l u m e 3 N u m b e r 1 0 ( O c t. '8 2 ) -----------
UNDOCUMENTED Z-80 OPCODES by Bill Smythe is reprinted
from the CHICATRUG NEWS (Chicago TRS-80 Users' Group).
NORTHERN BYTES editor's note: This is the most
comprehensive article that I have seen to date covering
this subject!
If you are willing to set aside your Editor/Assembler
for a while and take a direct look at the Z-80 opcodes,
certain patterns will become apparent. For example, of
the 256 possible opcodes (00 through FF) all but four
are in use as one-byte instructions. Some of these
stand alone; others are followed by one- or two-byte
operands. For example:
13 INC DE (no operand)
3E nn LD A,nn (1-byte operand)
10 dd DJNZ dd (1-byte operand)
01 nn mm LD BC,mmnn (2-byte operand)
The four missing opcodes are CB, DD, ED, and FD. These
serve as "escape codes" to alert the Z-80 that a
two-byte instruction is coming up. Examples:
CB C0 SET 0,B
DD 21 nn mm LD IX,mmnn
ED 80 LDIR
FD 2B DEC IY
Like the one-byte instructions, some two-byters are used
with operands, while others stand alone.
One of the first observations made by any Z-80 hacker is
the parallel among HL, IX, and IY instructions:
21 nn mm LD HL,mmnn
DD 21 nn mm LD IX,mmnn
FD 21 nn mm LD IY,mmnn
77 LD (HL),A
DD 77 jj LD (IX+jj),A
FD 77 jj LD (IY+jj),A
Almost any instruction referring to HL can be changed to
the corresponding instruction for IX or IY by prefixing
DD or FD, respectively. When HL appears in parentheses,
it becomes (IX+jj) or (IY+jj), where the index jj
appears in the opcode as the second byte following the
DD or FD. Meanwhile, the two-byte opcodes beginning
with CB form an orderly set of shift, rotate, set,
reset, and bit-test instructions, while the relatively
disorganized ED set performs a variety of useful tasks.
And then there are the combined prefixes DDCB and FDCB.
Their relationship to the CB codes are pretty much what
you would expect:
CB 46 BIT 0,(HL)
DD CB jj 46 BIT 0,(IX+jj)
FD CB jj 46 BIT 0,(IY+jj)
--------- T h e F u n B e g i n s -----------
Everything said so far is pretty much common knowledge,
well-documented by Zilog, the Z-80 manufacturer. But
what happens when DD or FD is prefixed to an instruction
not containing HL?
37 SCF
C3 nn mm JP mmnn
DD 37 ?????
FD C3 nn mm ?????
As far as I can determine, the prefixes in these cases
have no effect. The two instructions shown here
continue to function as SCF and JP mmnn, respectively.
But what if the instruction deals with either H or L,
but not HL?
24 INC H
2E nn LD L,nn
Just as the register pair HL is made up of two
registers, H and L, it appears that the 16-bit IX
register consists of two 8-bit registers, which I shall
call HX and LX. Similarly for IY. The above
instructions become:
DD 24 INC HX
DD 2E nn LD LX,nn
FD 24 INC HY
FD 2E nn LD LY,nn
The last instruction, for example, loads the low-order
half of the IY register with the value nn while leaving
the high-order half untouched.
If, however, an instruction contains both H and (HL), or
both L and (HL), then only the (HL) part is affected by
the addition of DD or FD:
66 LD H,(HL)
DD 66 jj LD H,(IX+jj)
FD 66 jj LD H,(IY+jj)
Adding a second DD or FD in front has no additional
effect. Apparently, there are no such instructions as
LD HX,(IX+jj) or LD HY,(IY+jj).
--------- W h a t ' s Y o u r C B H a n d l e ? -----------
The CB instructions are divided into four groups:
CB00 through CB3F: rotate and shift group
CB40 through CB7F: BIT testing
CB08 through CBBF: RESet group
CBC0 through CBFF: SET group
Of these four groups, all seem complete except for the
first. The first group is divided into eight subgroups
of eight instructions each:
CB00-CB07: RLC (rotate left circular)
CB08-CB0F: RRC (rotate right circular)
CB10-CB17: RL (rotate left through carry)
CB18-CB1F: RR (rotate right through carry)
CB20-CB27: SLA (shift left arithmetic)
CB28-CB2F: SRA (shift right arithmetic)
CB30-CB37: ???????
CB38-CB3F: SRL (shift right logical)
The missing CB30 group looks as though it ought to be a
shift left logical, whatever that is. Trouble is, SLA
(shift left arithmetic) is already pretty logical. So
what's left for SLL to do? As might be expected, SLL
shifts bits 0 through 6 leftward into bits 1 through 7,
while bit 7 goes into the carry flag. But then comes
the surprise -- bit 0 is set. Yes, Virginia, regardless
of the previous status of any bit, or of any flag, bit 0
is turned on. Thus SLL, in effect, multiplies by 2 and
adds 1. As with the other CB instructions, the affected
register is B, C, D, E, H, L, (HL), or A depending on
which instruction, CB30 through CB37, is used.
--------- C o m b i n a t i o n s A n d M o r e C o m b i n a t i o n s -----------
Of the combined opcodes, DDCBjjxx and FDCBjjxx, only
every eighth one is documented by Zilog:
DD CB jj 06 RLC (IX+jj)
DD CB jj 0E RRC (IX+jj)
(etc.)
One might not expect much from those not on the list,
since the corresponding DD-less CB instructions have
nothing to do with HL. Not so, however -- a lot of
weird stuff is going on here:
DD CB jj 00 RLC B,(IX+jj)
DD CB jj 01 RLC C,(IX+jj)
DD CB jj 02 RLC D,(IX+jj)
DD CB jj 03 RLC E,(IX+jj)
DD CB jj 04 RLC H,(IX+jj)
DD CB jj 05 RLC L,(IX+jj)
DD CB jj 06
DD CB jj 07 RLC A,(IX+jj)
-- and similarly for RRC, RL, RR, SLA, SRA, SLL, and
SRL. But what does that mean, "RLC B,(IX+jj)"? THat's
just a name I chose for a peculiar phenomenon in which
(IX+jj) is rotated left cirular, then copied into B. In
other words, RLC B,(IX+jj) is like RLC (IX+jj) followed
by LD B,(IX+jj).
The SET and RESet instructions are even more curious:
DD CB jj 80 RES B,0,(IX+jj)
DD CB jj 81 RES C,0,(IX+jj)
DD CB jj 82 RES D,0,(IX+jj)
DD CB jj 83 RES E,0,(IX+jj)
DD CB jj 84 RES H,0,(IX+jj)
DD CB jj 85 RES L,0,(IX+jj)
DD CB jj 86
DD CB jj 87 RES A,0,(IX+jj)
I don't know how many Editor/Assemblers could handle 3
operands, even if they recognized undocumented opcodes.
I couldn't think of any other way to express what
happens -- (IX+jj) first has bit 0 reset, then is copied
into the indicated register (e.g. B). The action is
equivalent to RES 0,(IX+jj) followed by LD B,(IX+jj).
Of course, the same can be done with bits 1 through 7,
with SET as well as RESet, and with IY as well as IX.
The BIT instructions are less interesting. Undocumented
codes DDCBjj40 through DDCBjj47 turn out to be
equivalent to the documented version. No copying into
registers B, C, D, etc. is done:
DD CB jj 40 BIT 0,(IX+jj)
DD CB jj 41 BIT 0,(IX+jj)
DD CB jj 42 BIT 0,(IX+jj)
DD CB jj 43 BIT 0,(IX+jj)
DD CB jj 44 BIT 0,(IX+jj)
DD CB jj 45 BIT 0,(IX+jj)
DD CB jj 46 BIT 0,(IX+jj)
DD CB jj 47 BIT 0,(IX+jj)
--------- L o t s o f R o o m f o r M o r e -----------
My investigations into the ED group yielded little of
interest. There were some duplications; for example,
the eight instructions ED44, ED4C, ED54, ED5C, ED64,
ED6C, ED74, ED7C all turned out to be NEG, even though
only the first is documented as such. I also found
duplicates for RETN, RETI, IM 0, IM 1, and IM 2. There
were also a couple of "expected" duplicates:
ED 63 nn mm LD (mmnn),HL
ED 6B nn mm LD HL,(mmnn)
-- but these instructions already exist, and execute
faster, in the non-ED set.
The ED group did provide a couple of lone curiosities:
ED 70 IN --,(C)
ED 71 OUT (C),--
These appear where you would expect the "missing" IN
(HL),(C) and OUT (C),(HL). Nothing happens with (HL),
though. IN --,(C) appears to function like IN A,(C), IN
B,(C), etc., except that the result does not go
anywhere. The flags, however, are set as expected. OUT
(C),-- seems to output a zero to the port.
I could not detect any action for the first and fourth
quarters of the ED set, ED00-ED3F and EDC0=EDFF.
Three-fourths of the third quarter is also "missing", as
are two instructions in the second quarter, ED77 and
ED7F. This leaves room for 178 more instructions --
anyone for an upgrade? I'd like to see instructions
like LD B,(DE) and CP (DE) and SUB (DE).
--------- E X C E P T I O N S -----------
I said that any HL instruction could be changed to IX or
IY by simply prefixing DD or FD. That was a little
white lie. The following instructions are not
convertible because they begin with ED:
ED 42 SBC HL,BC
ED 4A ADC HL,BC
ED 52 SBC HL,DE
ED 5A ADC HL,DE
ED 62 SBC HL,HL
ED 6A ADC HL,HL
ED 72 SBC HL,SP
ED 7A ADC HL,SP
ED 67 RRD
ED 6F RLD
In addition, the following instructions cannot be
converted even though they are one-byters:
D9 EXX
EB EX DE,HL
-- and the JP (HL) instruction becomes JP (IX) or JP
(IY), not JP (IX+jj) or JP (IY+jj):
E9 JP (HL)
DD E9 JP (IX)
FD E9 JP (IY)
--------- O n e a t a ' t i m e , P l e a s e -----------
Except for DDCB and FDCB, there is no benefit in
combining two or more of the four escape codes. There
are three cases:
(1) In the event of multiple DDs and/or FDs, all but
the last will be ignored.
(2) EDCB, EDDD, EDED, and EDFD will be ignored
entirely since they lie in the inoperative fourth
quarter of the ED set.
(3) If either DD or FD precedes ED, the former will
be ignored.
--------- A W o r d o f C a u t i o n -----------
To any machine-language programmers whose appetites may
have been whetted: Most Z-80 Editor/Assemblers do not
recognize undocumented opcodes, so you'll have to enter
these codes as DEFBs. More important, it is conceivable
that not all Z-80s will respond to these codes in the
same way. If you plan to sell your programs, the best
advice is not to use undocumented instructions.
--------- S u m m a r y o f U s e f u l U n d o c u m e n t e d Z - 8 0 O p c o d e s -----------
DD24 INC HX DD62 LD HX,D DD8C ADC A,HX
DD25 DEC HX DD63 LD HX,E DD8D ADC A,LX
DD26 nn LD HX,nn DD64 LD HX,HX DD94 SUB HX
DD2C INC LX DD65 LD HX,LX DD95 SUB LX
DD2D DEC LX DD67 LD HX,A DD9C SBC A,HX
DD2E nn LD LX,nn DD68 LD LX,B DD9D SBC A,LX
DD44 LD B,HX DD69 LD LX,C DDA4 AND HX
DD45 LD B,LX DD6A LD LX,D DDA5 AND LX
DD4C LD C,HX DD6B LD LX,E DDAC XOR HX
DD4D LD C,LX DD6C LD LX,HX DDAD XOR LX
DD54 LD D,HX DD6D LD LX,LX DDB4 OR HX
DD55 LD D,LX DD6F LD LX,A DDB5 OR LX
DD5C LD E,LX DD7C LD A,HX DDBC CP HX
DD5D LD E,LX DD7D LD A,LX DDBD CP LX
DD60 LD HX,B DD84 ADD A,HX
DD61 LD HX,C DD85 ADD A,LX
The corresponding instructions for HY and LY may be
obtained by using FD in place of DD.
CB30 SLL B CB34 SLL H
CB31 SLL C CB35 SLL L
CB32 SLL D CB36 SLL (HL)
CB33 SLL E CB37 SLL A
DDCBjj00-DDCBjj07 RLC r,(IX+jj)
DDCBjj00-DDCBjj0F RRC r,(IX+jj)
DDCBjj10-DDCBjj17 RL r,(IX+jj)
DDCBjj18-DDCBJJ1F RR r,(IX+jj)
DDCBjj20-DDCBjj27 SLA r,(IX+jj)
DDCBjj28-DDCBjj2F SRL r,(IX+jj)
DDCBjj30-DDCBjj37 SLL r,(IX+jj)
DDCBjj38-DDCBjj3F SRL r,(IX+jj)
DDCBjj80-DDCBjj87 RES r,0,(IX+jj)
DDCBjj88-DDCBjj8F RES r,1,(IX+jj)
DDCBjj90-DDCBjj97 RES r,2,(IX+jj)
DDCBjj98-DDCBjj9F RES r,3,(IX+jj)
DDCBjjA0-DDCBjjA7 RES r,4,(IX+jj)
DDCBjjA8-DDCBjjAF RES r,5,(IX+jj)
DDCBjjB0-DDCBjjB7 RES r,6,(IX+jj)
DDCBjjB8-DDCBjjBF RES r,7,(IX+jj)
DDCBjjC0-DDCBjjC7 SET r,0,(IX+jj)
DDCBjjC8-DDCBjjCF SET r,1,(IX+jj)
DDCBjjD0-DDCBjjD7 SET r,2,(IX+jj)
DDCBjjD8-DDCBjjDF SET r,3,(IX+jj)
DDCBjjE0-DDCBjjE7 SET r,4,(IX+jj)
DDCBjjE8-DDCBjjEF SET r,5,(IX+jj)
DDCBjjF0-DDCBjjF7 SET r,6,(IX+jj)
DDCBjjF8-DDCBjjFF SET r,7,(IX+jj)
In the last 3 tables, the corresponding instructions for
(IY+jj) may be obtained by using FD in place of DD. The
value of r is determined as follows:
Last digit of opcode: register r:
0 or 8 B
1 or 9 C
2 or A D
3 or B E
4 or C H
5 or D L
6 or E (blank)
7 or F A