SIGNAL LEVELS - FILL IN THE
BLANKS |
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A computer spread sheet is an easy way to determine RF signal
losses for high and low forward RF distribution frequencies. If a two-way active
design is desired, the highest and lowest return path frequency losses should also be
calculated. A sample spread sheet is shown below. Remember to enter the data
in a format that will account for the loss per 100-foot values given by cable
manufacturers. Entering the values with the decimal point moved two places to the
left will allow direct footage entries. |
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A |
B |
C |
D |
E |
F |
G |
P3-500 Cable
dB Loss per foot >> |
5 MHz |
40 MHz |
50 MHz |
RF Level |
750 MHz |
RF Level |
0.0016 |
0.0044 |
0.0050 |
35 |
0.0204 |
40 |
2-way splitter |
-3.8 |
-3.9 |
-3.9 |
31.1 |
-4.9 |
35.1 |
300 |
-0.48 |
-1.32 |
-1.50 |
29.6 |
-6.12 |
29.0 |
23 dB, 4-port tap |
-0.5 |
-0.7 |
-0.7 |
28.9 |
-1.4 |
27.6 |
80 |
-0.13 |
-0.35 |
-0.4 |
28.5 |
-1.63 |
24.9 |
20 dB, 4-port tap |
-0.6 |
-0.7 |
-0.7 |
27.8 |
-1.5 |
23.4 |
80 |
-0.13 |
-0.35 |
-0.4 |
27.4 |
-1.63 |
21.8 |
17 dB, 8-port tap |
-1.6 |
-1.7 |
-1.7 |
25.7 |
-2.6 |
19.2 |
80 |
-0.13 |
-0.35 |
-0.4 |
25.3 |
-1.63 |
17.6 |
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The table above shows cable footage and passive device descriptions
in the first column on the left. Cable losses and passive losses are shown in the
second and third columns. In a spread sheet, the formula in each of these cells
would be entered to multiply the cable footage in the first column by the loss per foot
near the top of each frequency column. The formula in cell
B4 would take the form of +$A4*B$2
and display the value 0.48 dB loss
as shown in the 5 MHz column to the right of the 300 feet of cable
distance in the first column. The dollar signs in the formula will
insure that each formula copied below that cell will point to the cable distances in
column A and the correct loss of the cable per foot at that frequency. That same formula can then be copied into all the cells in that
column and in columns C, D and F. When
a cable footage is entered in column A, the attenuation at 5 MHz will appear in column B. When
a passive device is entered in row cell in column A, enter the insertion loss for that
device at the designated frequencies, replacing the fomula in the appropriate cells on
that row in B, C, D and F columns. With all the losses in place, the RF
signal levels can be found and displayed in columns E and G. |
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The RF amplifier output level at 50
MHz is entered in cell E2. The 750
MHz output level is entered in cell G2. Each cell in column E and G,
beginning with row 3, will have a formula which takes the signal level from the cell above
and subtracts the loss of the adjacent cell to the left from the value above. The
formula in cell E3 would read +E2-D3 and
display the value of 31.1 dBmV. Copy that formula in all cells below that one in
column E. A similar set of formulas would be in column G to calculate the signal
levels at the output of each device or after a length of cable at 750 MHz. |
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Looking at the chart, it becomes obvious by looking at the RF
signal levels in columns E and G, that the cable and passive losses are reversing the
slope output of the amplifier as the signal propogates down the signal path. This
chart represents the path from the RF amplifier to the end of cable A as
shown in the sample diagram on the previous page of this article. It appears
that one more tap and a short length of cable may fit into this scenario before a second
amplifier is required. Be sure that the highest frequency has at least 3 to 5 dBmV
more signal than the rated noise figure of the amplifier that is going to be used.
This is discussed in the technical article "Amplifier
Operational Sweet Spot." A cable equalizer installed in the input
of that next amplifier will insure a uniform carrier-to-noise ratio (C/N) for the RF
signals. Choosing the correct equalizer is also covered in a technical article
titled "Fixed Equalizer Selection Theory and
Chart." |
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With all this said, it is time to build your own system, using real
cable and passive loss data from your system as it exists or is proposed to meet the cable
distances involved. It may be necessary to increase the output levels and slope of
the amplifiers used in the system to meet spacing requirements. Larger cable sizes
may have to be used. Lower bandwidths ease this problem, but signal levels reaching
the television sets are not negotiable. Good Luck! Call or email me if you
need additional help. Jerry K. Thorne, Applications Engineer, Quality RF
Services, Inc. jthorne@qrf.com
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