Most
LEDs have their characteristics specified at a current of 20 mA. If
you want really good reliability and you are not certain you don't
have worse-than-average heat conductivity in your mounting, heat buildup
in wherever you mount them, voltage/current variations, etc. then
design for 15 milliamps.
Now
for how to make 15 milliamps flow through the LED:
First
you need to know the LED voltage drop. It is safe enough to assume
1.7 volts for non-high-brightness red, 1.9 volts for high-brightness,
high-efficiency and low-current red, and 2 volts for orange and yellow,
and 2.1 volts for green. Assume 3.4 volts for bright white, bright
non-yellowish green, and most blue types. Assume 4.6 volts for 430
nM bright blue types such as Everbright and Radio Shack. Design for
12 milliamps for the 3.4 volt types and 10 milliamps for the 430 NM
blue.
You
can design for higher current if you are adventurous or you know you
will have a good lack of heat buildup. In such a case, design for
25 ma for the types with voltage near 2 volts, 18 ma for the 3.4 volt
types, and 15 ma for the 430 NM blue.
Meet
or exceed the maximum rated current of the LED only under favorable
conditions of lack of heat buildup. Some LED current ratings assume
some really favorable test conditions - such as being surrounded by
air no warmer than 25 degrees Celsius and some decent thermal conduction
from where the leads are mounted. Running the LED at specified laboratory
conditions used for maximum current rating will make it lose half
its light output after rated life expectancy (20,000 to 100,000 hours)
- optimistically! You can use somewhat higher currents if you heat-sink
the leads and/or can tolerate much shorter life expectancy.
Next,
know your supply voltage. It should be well above the LED voltage
for reliable, stable LED operation. Use at least 3 volts for the lower
voltage types, 4.5 volts for the 3.4 volt types, and 6 volts for the
430 NM blue.
The
voltage in most cars is 14 volts while the alternator is successfully
charging the battery. A well-charged 12 volt lead-acid battery is
12.6 volts with a light load discharging it. Many "wall wart" DC power
supplies provide much higher voltage than specified if the load is
light, so you need to measure them under a light load that draws maybe
10-20 milliamps.
Next
step is to subtract the LED voltage from the supply voltage. This
gives you the voltage that must be dropped by the dropping resistor.
Example: 3.4 volt LED with a 6 volt supply voltage. Subtracting these
gives 2.6 volts to be dropped by the dropping resistor.
The
next step is to divide the dropped voltage by the LED current to get
the value of the dropping resistor. If you divide volts by amps, you
get the resistor value in ohms. If you divide volts by milliamps,
you get the resistor value in kilo-ohms or k.
Example:
6 volt supply, 3.4 volt LED, 12 milliamps. Divide 2.6 by .012. This
gives 217 ohms. The nearest standard resistor value is 220 ohms.
If
you want to operate the 3.4 volt LED from a 6 volt power supply at
the LED's "typical" current of 20 ma, then 2.6 divided by .02 yields
a resistor value of 130 ohms. The next higher popular standard value
is 150 ohms.
If
you want to run a typical 3.4 volt LED from a 6 volt supply at its
maximum rated current of 30 ma, then divide 2.6 by .03. This indicates
87 ohms. The next higher popular standard resistor value is 100 ohms.
Please beware that I consider the 30 ma rating for 3.4-3.5 volt LEDs
to be optimistic.
One
more thing to do is to check the resistor wattage. Multiply the dropped
voltage by the LED current to get the wattage being dissipated in
the resistor. Example: 2.6 volts times .03 amp (30 milliamps) is .078
watt. For good reliability, I recommend not exceeding 60 percent of
the wattage rating of the resistor. A 1/4 watt resistor can easily
handle .078 watt. In case you need a more powerful resistor, there
are 1/2 watt resistors widely available in the popular values.
You
can put LEDs in series with only one resistor for the whole series
string. Add up the voltages of all the LEDs in the series string.
This should not exceed 80 percent of the supply voltage if you want
good stability and predictable current consumption. The dropped voltage
will then be the supply voltage minus the total voltage of the LEDs
in the series string.
Do
not put LEDs in parallel with each other. Although this usually works,
it is not reliable. LEDs become more conductive as they warm up, which
may lead to unstable current distribution through paralleled LEDs.
LEDs in parallel need their own individual dropping resistors. Series
strings can be paralleled if each string has its own dropping resistor.
Copyright:
Don Klipstein, Jr. 01/01/00